How to connect spirals in a muffle furnace so that the power becomes less?

Hello, I made a muffle ceramics kiln about 30 45 l. The furnace has 6 spirals made of nichrome 2 mm thick. When measuring with current clamps, it gives 150 amperes, i.e., when calculating 220, multiply by 150 is equal to 30 kW. The connection of the spirals in the photo. Question: how to connect the outputs of 6 spirals so that there is less power consumption.

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Posted: 26.11.2018 Updated: 26.11.2018 4 comments

4 comments

Admin

11/26/2018 at 09:08

Well, you connected 2 in series in three parallel circuits. Connect 3 in series in two parallel circuits. but note that this will lower the heating temperature. The Joule-Lenz law in this case is in all its glory.

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- Basil
  
  11/26/2018 at 16:16
  
  What is it like ? Please draw. And what will be the load on the network?. And is it even possible to use a furnace like mine on a regular network
  
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  - Admin
    
    11/26/2018 at 16:54
    
    So measure the resistance and count! Or rebuild the circuit and measure the current. The load will decrease as resistance will increase. The current will be about 100 amperes. The load will be 22 kW.
    Where did you get such input in one phase? Such things, even by the rules, should be three-phase
    
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Basil

11/27/2018 at 15:27

Thank you. Tell me how to connect for a three-phase network

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